x^2-7x+12=(x-4)(x-3)

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Solution for x^2-7x+12=(x-4)(x-3) equation: 



x^2-7x+12=(x-4)(x-3)

We move all terms to the left:

x^2-7x+12-((x-4)(x-3))=0

We multiply parentheses ..

x^2-((+x^2-3x-4x+12))-7x+12=0



We calculate terms in parentheses: -((+x^2-3x-4x+12)), so:

(+x^2-3x-4x+12)

We get rid of parentheses

x^2-3x-4x+12

We add all the numbers together, and all the variables

x^2-7x+12

Back to the equation:

-(x^2-7x+12)



We add all the numbers together, and all the variables

x^2-7x-(x^2-7x+12)+12=0

We get rid of parentheses

x^2-x^2-7x+7x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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